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July 24, 2014

July 24, 2014

Posted by **Jose** on Tuesday, August 24, 2010 at 8:30am.

- Trig -
**Reiny**, Tuesday, August 24, 2010 at 8:38amcheck your typing, your statement is not true.

- Trig -
**Reiny**, Tuesday, August 24, 2010 at 8:50amI figured you must mean

1/(secØtanØ) - cscØ = - sinØ

Proof:

LS = 1/((1/cosØ)(sinØ/cosØ)) - 1/sinØ

= cos^2 Ø/sinØ - 1/sinØ

= (cos^ Ø - 1)sinØ

= - sin^2 Ø/sinØ

= =sinØ

= RS

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