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September 1, 2014

September 1, 2014

Posted by **Courtney** on Tuesday, August 24, 2010 at 8:22am.

This is all I know how to do and don't know if it's even right. Or what to do from here.

5(4r-3c)-2(7r-9c)=0 solve for r

20r-15c-14r-11c=0

6r-26c=0

- Maath -
**Reiny**, Tuesday, August 24, 2010 at 8:41amsee the post above this, follow the same steps

- Maath -
**Courtney**, Tuesday, August 24, 2010 at 9:21amthis is the steps:

20r-15c-14r+18c=0

6r+3c=0

so for my final answer I got r=c/2 is that correct?

- Maath -
**Reiny**, Tuesday, August 24, 2010 at 9:33amclose ...

from your second last line

6r + 3c = 0

6r = - 3c

r = -c/2

btw, I am glad you caught your error in the steps of your original at the top,

where did the -11c come from?

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