Saturday

December 20, 2014

December 20, 2014

Posted by **Thomas** on Tuesday, August 24, 2010 at 3:30am.

Particle #1: x(t)=2t^2-4

Particle #2: x(t)= -3t-4

Particle #3: -2t^2-4

Particle #4: 2 *[sq. root (t+1)] -4

Which of these particles are speeding up for 0<t< infinity?

a)#1 only

b)#1,3,4

c)all four

d)none

e)#1,4

- college physics -
**drwls**, Tuesday, August 24, 2010 at 10:31amIf you consider "speeding up" to be an increase in speed, regardless of direction, then none of the choices is correct.

#2 and #3 accelerate, backwards. The others start out by slowing down.

They may be referring to increasing speed as an increase in V in the positive direction.

**Answer this Question**

**Related Questions**

College Physics - four particles are fixed along an x axis, separated by ...

AP CALC. AB - 1.The position of a particle moving on the line y = 2 is given by ...

Calculus (Derivatives) - Two particles are moving in straight lines. The ...

Calculous - A particle moves along the c-axis so that at time t its position is ...

calculus - 5. A particle moves along the y – axis with velocity given by v(t)=...

College Physics - particle 1 of charge q1 = 1.04 ěC and particle 2 of charge q2...

physics - A particle moves along the x-axis according to the equation x = 50.0t...

calculus - a particle moves along a number line measured in cm so that its ...

Calc - A particle moves along the x-axis in such a way that it's position in ...

Calc - A particle moves along the x-axis in such a way that it's position in ...