Tuesday

March 31, 2015

March 31, 2015

Posted by **christy** on Tuesday, August 24, 2010 at 12:24am.

This is what I have so far, then I am lost

t1= 55/r t2=15/r-5 =4

r (r-5) (55/r + 15/r-5) =4

55 (r-5) +15r=4r (r-5)

55r-275 + 15r=4r^2-20r

Now I am lost.

- algebra word problem -
**Quidditch**, Tuesday, August 24, 2010 at 2:13amYou are practically there!

Combine terms and rearrange to get into the form:

4r^2 -90r + 275 = 0

Use the quadratic formula to find r. There will be two answers. One of the answers is the result if the canoeist reverses direction (r-5 is negative).

- algebra word problem -
**Quidditch**, Tuesday, August 24, 2010 at 2:25amr-5 being negative results in a negative t2 and so should be ignored.

**Answer this Question**

**Related Questions**

Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...

algebra - during the first part of a trip a canoeist travels 64 miles at a ...

algebra - During the first part of a trip a canoeist travels 71 miles at a ...

Algebra - Please HELP - During the first part of a trip a canoeist travels 49 ...

algebra 2 - During the first part of a trip a canoeist travels 26 miles at a ...

Algebra - During the first part of a trip, a canoeist travels 57 miles at a ...

algebra - During the first part of a trip, a canoeist travels 69 miles at a ...

Algebra - During the first part of a trip a canoeist travels 49 miles at a ...

ALGEBRA - DURING THE FIRST PART OF A TRIP, A CANOEIST TRAVELS 35 MILES AT A ...

algebra 2 - during the first part of a trip, a canoeist travels 47 miles at a ...