By throwing a ball at an angle of 50 degrees, a girl can throw it a maximum horizontal distance of R = 38 m on a level field.

(a) How far can she throw the same ball vertically upward? Assume that her muscles give the ball the same speed in each case.

(b) Is this assumption valid?

To solve this problem, we can use the concept of projectile motion.

(a) To find the maximum vertical distance the girl can throw the ball, we need to calculate the vertical component of the initial velocity. Remember, the initial velocity can be split into horizontal and vertical components based on the given angle of 50 degrees.

We have the horizontal component of velocity (Vx) which remains constant throughout the motion. The vertical component of velocity (Vy) follows a parabolic trajectory under the effect of gravity.

Using the equation for the range of projectile motion, we can write:

R = Vx * t

where R is the horizontal distance (38 m) and Vx is the horizontal component of velocity.

Since the time of flight (t) is the same for both the horizontal and vertical motions, we can use this equation to find Vx:

Vy = V * sin(θ)

where Vy is the vertical component of velocity and θ is the launch angle (50 degrees).

Now, we can calculate Vy using trigonometry:

Vy = V * sin(50°)

To find the maximum vertical distance (Hmax), we can use the equation of motion in the y-direction:

Hmax = (Vy^2) / (2g)

where g is the acceleration due to gravity.

Using the values we obtained, we can substitute them into the equation:

Hmax = ((V * sin(50°))^2) / (2g)

Substituting g = 9.8 m/s^2, we can find the maximum vertical distance she can throw the ball.

(b) Now, to address whether the assumption is valid that her muscles give the ball the same speed in each case, we need to consider the effects of air resistance and other factors. In reality, it is unlikely that the ball will have exactly the same speed in both cases due to factors such as air resistance, arm angle, release speed, etc.

Therefore, the assumption that her muscles give the ball the same speed in each case might not be entirely valid. However, for the purposes of this problem, we make this assumption to find a solution based on theoretical calculations.