Posted by **kamleen** on Monday, August 23, 2010 at 10:53am.

3x + 2y + 16x^3z + 6y =

ANSWER: 19x + 8y + 3z

- math -
**Reiny**, Monday, August 23, 2010 at 10:58am
again, incorrect

when you add/subtract terms they must be "like"

the variables and exponents do not change.

3x + 2y + 16x^3z + 6y

= 3x + 8y + 16x^3z

(the only terms that were "like" were the y terms )

- math -
**PsyDAG**, Monday, August 23, 2010 at 10:59am
If the problem has no typos, it can reduce to:

16x^3z + 8y + 3x

- math -
**kamleen**, Monday, August 23, 2010 at 11:24am
the question is i wrote it wrong

3x + 2y + 16x + 3z + 6y =

- math -
**Reiny**, Monday, August 23, 2010 at 11:29am
So what is your answer?

I see three kind of terms, x's , y's and z's

- math -
**kamleen**, Monday, August 23, 2010 at 8:29pm
19x + 8y + 3z

- math -
**PsyDAG**, Tuesday, August 24, 2010 at 11:17am
Right.

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