3x + 2y + 16x^3z + 6y =

ANSWER: 19x + 8y + 3z

again, incorrect

when you add/subtract terms they must be "like"
the variables and exponents do not change.

3x + 2y + 16x^3z + 6y
= 3x + 8y + 16x^3z

(the only terms that were "like" were the y terms )

If the problem has no typos, it can reduce to:

16x^3z + 8y + 3x

the question is i wrote it wrong

3x + 2y + 16x + 3z + 6y =

So what is your answer?

I see three kind of terms, x's , y's and z's

19x + 8y + 3z

Right.

To simplify the given expression, we need to combine like terms.

First, let's combine the terms with the same variable (x). We have 3x and 16x^3z. To combine them, we add their coefficients: 3x + 16x^3z = (3 + 16x^2z)x.

Next, let's combine the terms with the same variable (y). We have 2y and 6y. To combine them, we add their coefficients: 2y + 6y = 8y.

Finally, we have the simplified expression: (3 + 16x^2z)x + 8y + 3z.

So, the answer is 19x + 8y + 3z.