what is equation of the line (- 3,0) and (0,4) y = please help me it is due tonight and I ma struggling to past his class
y=mx+b(Slope-intercept)
Slope= 4-0/0-(-3)
Slope= 4/3
then put a point in the formula.
4=0x4/3+b
so b=4
final equation: y=4/3x+4
thank you
your welcome:)
To find the equation of the line passing through the points (-3, 0) and (0, 4), you can use the slope-intercept form of a linear equation, which is y = mx + b.
Step 1: Find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates (-3, 0) and (0, 4):
m = (4 - 0) / (0 - (-3))
= 4 / 3
Step 2: Use one of the given points (0, 4) and the slope (m) to find the y-intercept (b). Substitute the values into the slope-intercept form, y = mx + b, and solve for b.
4 = (4/3)(0) + b
b = 4
Step 3: Now that you have the value of m (slope) as 4/3 and b (y-intercept) as 4, you can write the equation of the line as:
y = (4/3)x + 4
Therefore, the equation of the line passing through the points (-3, 0) and (0, 4) is y = (4/3)x + 4.