Posted by **Aless** on Sunday, August 22, 2010 at 2:37pm.

Use the quadratic formula to find the real solutions:

2x/x-3 + 2/x = 3

I know I multiply both sides by x(x-3), but I don't know how to do that.

- Algebra -
**Reiny**, Sunday, August 22, 2010 at 3:36pm
rewrite the equation as ...

[2x/(x-3)](x(x-3)) + [2/x](x(x-3)) = 3(x(x-3))

notice in the first term, x-3 on top cancels x-3 at the bottom, in the second term x on top cancels x at the bottom , to get ...

2x(x) + 2(x-3) = 3x^2 - 9x

2x^2 + 2x - 6 = 3x^2 - 9x

x^2 - 11x + 6 = 0

x = (11 ± √97)/2

- Algebra -
**Aless**, Sunday, August 22, 2010 at 3:53pm
thank you!

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