Algebra
posted by Aless .
Use the quadratic formula to find the real solutions:
2x/x3 + 2/x = 3
I know I multiply both sides by x(x3), but I don't know how to do that.

rewrite the equation as ...
[2x/(x3)](x(x3)) + [2/x](x(x3)) = 3(x(x3))
notice in the first term, x3 on top cancels x3 at the bottom, in the second term x on top cancels x at the bottom , to get ...
2x(x) + 2(x3) = 3x^2  9x
2x^2 + 2x  6 = 3x^2  9x
x^2  11x + 6 = 0
x = (11 ± √97)/2 
thank you!