Posted by joy on Sunday, August 22, 2010 at 9:54am.
Can you double check if figure 1 looks like this:
http://img823.imageshack.us/img823/6783/1282485265.png
If this is the case, then
equate energies, namely potential and kinetic energies:
Change in potential energy, ΔEp=mg(y2-y1)
Change in kinetic energy, ΔEk=(1/2)m(v2²-v1²)
By the law of conservation of energy, we have
ΔEp+ΔEk=0
Substitute and solve for v2, noting that v1=0.
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