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September 30, 2014

September 30, 2014

Posted by **Avery** on Sunday, August 22, 2010 at 8:11am.

dimensions of the lot be so that the enclosed area is as large as possible? (I'm supposed to solve this using a quadratic equations but I don't know how...)

- Math -
**bobpursley**, Sunday, August 22, 2010 at 8:26amarea=lenght*width

240=length+2widdth

or length=240-2W

area=(240-2w)w

So where are the zeroes? at w=0, and w=120.

Where is the maximum? halfway between the zeroes, or at 60=width

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