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Math

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240 m of fencing material is going to be used to enclose three sides of a rectangular lot. What should the
dimensions of the lot be so that the enclosed area is as large as possible? (I'm supposed to solve this using a quadratic equations but I don't know how...)

  • Math -

    area=lenght*width
    240=length+2widdth
    or length=240-2W

    area=(240-2w)w
    So where are the zeroes? at w=0, and w=120.

    Where is the maximum? halfway between the zeroes, or at 60=width

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