Posted by Avery on .
240 m of fencing material is going to be used to enclose three sides of a rectangular lot. What should the
dimensions of the lot be so that the enclosed area is as large as possible? (I'm supposed to solve this using a quadratic equations but I don't know how...)

Math 
bobpursley,
area=lenght*width
240=length+2widdth
or length=2402W
area=(2402w)w
So where are the zeroes? at w=0, and w=120.
Where is the maximum? halfway between the zeroes, or at 60=width