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February 1, 2015

February 1, 2015

Posted by **tommy** on Sunday, August 22, 2010 at 2:53am.

- physics -
**drwls**, Sunday, August 22, 2010 at 7:19amVo = 70 mph = 102.7 ft/s = 31.3 m/s

The average speed while decelerating must be Vo/2 = 15.65 m/s

Deceleration time = 90 m/(avg. speed) = 5.75 s

Deceleration rate = Vo/(deceleration time) = 31.3/5.75 = 5.44 m/s^2

Check: distance travelled while decelerating =

Vo*t - (a/2)t^2 = 31.3*5.75 - (2.72)(5.75)^2 = 90 m

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