Homework Help: physics

Posted by tommy on Sunday, August 22, 2010 at 2:53am.

A driver in a car traveling at a speed of 70 mi/h sees a deer 90 m away on the road. Calculate the minimum constant acceleration that is necessary for the car to stop without hitting the deer (assuming that the deer does not move in the meantime).

physics - drwls, Sunday, August 22, 2010 at 7:19am
Vo = 70 mph = 102.7 ft/s = 31.3 m/s

The average speed while decelerating must be Vo/2 = 15.65 m/s

Deceleration time = 90 m/(avg. speed) = 5.75 s

Deceleration rate = Vo/(deceleration time) = 31.3/5.75 = 5.44 m/s^2

Check: distance travelled while decelerating =
Vo*t - (a/2)t^2 = 31.3*5.75 - (2.72)(5.75)^2 = 90 m

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