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September 20, 2014

September 20, 2014

Posted by **Isabel** on Sunday, August 22, 2010 at 1:00am.

4.23= -.19t^2+2.56t-2.37

how do i find the value of t?

- Math -
**Quidditch**, Sunday, August 22, 2010 at 1:07amPut the equation into the form

ax^2 + bx + c = 0

then use the quadratic formula to find the solutions.

- Math -
**drwls**, Sunday, August 22, 2010 at 1:12amRewrite it in standard quadratic form as:

0.19t^2 - 2.56 t +6.60 = 0

The coefficients and constant are:

a = 0.19

b = -2.56

c = 6.6

Then use the quadratic formula for the two roots:

t = [-b +/1 sqrt(b^2-4ac)]/2a

One of the solutions is exactly 10.

The other is 3.4737

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