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Posted by on Sunday, August 22, 2010 at 1:00am.

If i'm given the equation

4.23= -.19t^2+2.56t-2.37

how do i find the value of t?

  • Math - , Sunday, August 22, 2010 at 1:07am

    Put the equation into the form
    ax^2 + bx + c = 0
    then use the quadratic formula to find the solutions.

  • Math - , Sunday, August 22, 2010 at 1:12am

    Rewrite it in standard quadratic form as:
    0.19t^2 - 2.56 t +6.60 = 0

    The coefficients and constant are:
    a = 0.19
    b = -2.56
    c = 6.6

    Then use the quadratic formula for the two roots:

    t = [-b +/1 sqrt(b^2-4ac)]/2a

    One of the solutions is exactly 10.
    The other is 3.4737

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