Posted by Sar on .
As shown in the figure, a square has sides of 8.0 cm with a charge of +6.0 µC at one corner (a) and with charges of 2.0 µC at the remaining three corners (b, c, and d).
The figure is just a square with no measurements. Corner a being the top left corner, corner b top right corner, corner d is bottom left, and corner c is bottom right.
Find the electric field at the center of the square.
___ N/C towards corner C.
I've tried working this problem out a few ways. Like using (8.99e9)(6.0e6)/8.0cm
&
(8.99e9)(2.0e6)/8.0cm
I get answers ranging from 5.3e8 N/C to 11.22 N/C.
Any suggestions?

Physics 1112 Electric charge 
bobpursley,
Well, if all the corners had the same charge, the E would be zero. So you are really just dealing with the excess charge: At a, you have a +8microC excess (assuming 2microC starting at each corner). Well, The E will be
E=kQexcess/distance^2
Qexcess is 8microC, distance is the distance from a to the center (8cm*.707)
, of course, distance has to be in meters.
Check my thinking. 
Physics 1112 Electric charge 
Sar,
Still couldn't get the correct answer :[