Posted by Gerald on Saturday, August 21, 2010 at 12:28pm.
I think it is easier if you assume some arbitrary number for the volume of acetic acid. Something like 100 mL.
moles acetic acid = M x L.
moles NaOH when 60 mL acetic acid have been neutralized = M x L.
Then use the Henderson-Hasselbalch equation to solve for pH.
2. I would assume a volume for the room, use PV = nRT to determine the number of moles at some P and T, convert to number of molecules and go from there. Another approach is to take a volume of 1 L, you know the density of air is about 1.29 g/L, convert to molecules/L, then take the cube root to convert to molecules along one side and convert to distance between molecules.
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