Figure is triangle c is biggest side, a and b are same size
19.
In figure-4, compute c if a = 3 and b = 2.
20.
In figure-4, compute b assuming 27a= and c =2b. ()
We do not have figure-4.
19. If this is a rt triangle:
c^2 = a^2 + b^2 = 9 + 4 =13,
c = sqrt (13) = 3.61
20. 27a = ? Please clarify.
To compute the value of side c, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (longest side) is equal to the sum of the squares of the other two sides.
In Figure-4, we have a triangle with side a = 3, side b = 2, and c as the longest side. Since a and b are the same size, we can assume that this is an isosceles triangle, where the two equal sides are a and b.
To find the value of c, we can use the Pythagorean theorem: c^2 = a^2 + b^2.
Substituting the values of a and b into the formula, we get:
c^2 = 3^2 + 2^2
c^2 = 9 + 4
c^2 = 13
To get the value of c, we can take the square root of both sides:
c = sqrt(13) ≈ 3.61 (rounded to two decimal places).
Therefore, the value of c in Figure-4 is approximately 3.61.
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To compute the value of side b, we can solve the given equation 27a = c = 2b.
In Figure-4, we have the following conditions: c = 2b and 27a = c.
Substituting c = 2b into the equation 27a = c, we get:
27a = 2b
Now, we need to determine a relationship between a and b to proceed. Since the values of a and b are not given, we cannot directly solve for either of them.
However, we can use the fact that a and b are the same size in an isosceles triangle. This means that a = b.
Substituting a = b into the equation 27a = 2b, we get:
27a = 2a
Now, we can solve this equation for the value of a:
27a - 2a = 0
25a = 0
a = 0
Since a = 0, we can substitute this value back into the equation 27a = 2b to solve for b:
27(0) = 2b
0 = 2b
b = 0
Therefore, the value of b in Figure-4 is 0.