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November 24, 2014

November 24, 2014

Posted by **Anonymous** on Thursday, August 19, 2010 at 11:28pm.

- MATH -
**drwls**, Friday, August 20, 2010 at 9:55amP(A) + P(B) + P(C) = 1 = 5P(A)

P(A) = P(B) = 1/5

P(C) = 2/5

- MATH -
**PsyDAG**, Friday, August 20, 2010 at 11:12amI don't know how drwls got 5P(A).

P(A) + P(B) + P(C) = 1

P(A) + P(A) + 2P(A) = 1 = 4P(A)

P(A) = 1/4 = P(B)

P(C) = 2P(A) = 1/2

- MATH -
**drwls**, Saturday, August 21, 2010 at 8:46pmYes, my mistake.

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