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I can not see your equation but assume it is of the form
W = C/r^2
r^2 = C/W
r = sqrt (C/W)
Now sea level in feet is
r = 3963 miles (5280 ft/mile) = 20.9 * 10^6 feet
100 = C/(20.9*10^6)^2
C = 4.37*10*16
In death valley r = 20.9*10^6 - 282
r = 20.899*10^6
r^2 = 436.8*10*12
W = 100.05 tiny bit heavier
do the same thing on the mountain. It will be slightly lighter
For the second problem I also can not see your formula
It will be of form
D =sqrt (h(2R+h))
if h <<r (which it is here)
D = sqrt (2 R h)
D^2 = 2 R h
h = D^2/(2R)
see how far you can see the horizon from Long's peak (find D for h = height of Long's peak)
then see how far you can see from Cheyenne (You will have to look up how high the city is)
add those two to find out if it is more than 89 miles.
We will have to assume that nothing sticks up between them.
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