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March 30, 2015

March 30, 2015

Posted by **Cendrillion** on Thursday, August 19, 2010 at 5:42pm.

- geometry -
**drwls**, Thursday, August 19, 2010 at 6:29pmDraw a regular hexagon. It consists of six equilateral triangles. Each has a "height" of 0.65m (measured between two opposite sides). The "width" of the hexagon, measured between opposite corners, is 2R, where R is the radius of the circumscribed circle, which is 0.65/sin60 = 0.75056 m

Double that for the width: 1.5011 m

Round off to 1.5.

- geometry -
**Cendrillion**, Thursday, August 19, 2010 at 9:04pmthank you. I knew the equilateral triangles played a part, but I was confused because only one measurement was given.

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