Posted by **Ray** on Tuesday, August 17, 2010 at 8:12pm.

Center and radius of x^2 + y^2 – 4y = 0.

- geometry -
**Henry**, Tuesday, August 17, 2010 at 9:39pm
STD Form of Circle:

(x - h)^2 + (y - k)^2 = r^2, C(h , k).

x^2 + y^2 - 4y = o,

Complete the square:

x^2 + y^2 - 4y + (-4 / 2)^2 = (-4/2)^2,

x^2 + y^2 - 4y + 4 = 4,

Convert the perfect sq to a binomial:

(x - 0 )^2 + (y - 2)^2 = 4 = r^2, r=2.

C(0 , 2).

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