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March 30, 2017

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Center and radius of x^2 + y^2 – 4y = 0.

  • geometry - ,

    STD Form of Circle:
    (x - h)^2 + (y - k)^2 = r^2, C(h , k).

    x^2 + y^2 - 4y = o,
    Complete the square:
    x^2 + y^2 - 4y + (-4 / 2)^2 = (-4/2)^2,
    x^2 + y^2 - 4y + 4 = 4,
    Convert the perfect sq to a binomial:
    (x - 0 )^2 + (y - 2)^2 = 4 = r^2, r=2.
    C(0 , 2).

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