If c= 16 and B= 67 degrees, find a.
If this is a right triangle, then
cosB=a/c
and you can solve for c from that.
cos=3
To find a, we need to use the law of cosines, which states that for any triangle with sides a, b, and c, and angle C opposite side c, the following equation holds:
c^2 = a^2 + b^2 - 2abcos(C)
Given that c = 16 and B = 67 degrees, we can substitute the values into the equation:
16^2 = a^2 + b^2 - 2abcos(67)
Simplifying further:
256 = a^2 + b^2 - 2abcos(67)
Now, we need more information about the triangle. Do you have any other values or measurements that we can use to find a and b?