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March 29, 2017

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Find the value of K so that the point P lies on the line L.

1. P(2,1), L: 3x + Ky = 8

2. P(2,2), L: Kx + (K + 1)y = 2

Help me i have no idea how to do this! :[

  • Algebra 2 - ,

    in your given point, the first number is the x value, the second number is the y value.
    So just substitute.
    3(2) + k(1) = 8
    6 + k = 8
    k = 2

    Do the second one the same way, let me know what you got.

  • Algebra 2 - ,

    Is this right?

    k(2) + 2 = -k(2) + 2
    4k = 0
    k = 0

  • Algebra 2 - ,

    Your last two lines are correct, but how did you get your first line from the given equation

    My line would have been

    k(2) + (k+1)(2) = 2
    then
    2k + 2k + 2 = 2
    leading to your last two lines.

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