Posted by **Jessica** on Tuesday, August 17, 2010 at 7:05pm.

Find the value of K so that the point P lies on the line L.

1. P(2,1), L: 3x + Ky = 8

2. P(2,2), L: Kx + (K + 1)y = 2

Help me i have no idea how to do this! :[

- Algebra 2 -
**Reiny**, Tuesday, August 17, 2010 at 7:28pm
in your given point, the first number is the x value, the second number is the y value.

So just substitute.

3(2) + k(1) = 8

6 + k = 8

k = 2

Do the second one the same way, let me know what you got.

- Algebra 2 -
**Jessica**, Tuesday, August 17, 2010 at 7:51pm
Is this right?

k(2) + 2 = -k(2) + 2

4k = 0

k = 0

- Algebra 2 -
**Reiny**, Tuesday, August 17, 2010 at 7:56pm
Your last two lines are correct, but how did you get your first line from the given equation

My line would have been

k(2) + (k+1)(2) = 2

then

2k + 2k + 2 = 2

leading to your last two lines.

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