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December 20, 2014

December 20, 2014

Posted by **kamleen** on Tuesday, August 17, 2010 at 3:26pm.

1) (x^2 + x - 6) / (x - 2)=

2) 24b^4C^3 / 6b^2c=

3) (3p^2 + pq - 2q^2)/ (p + q)=

- math -
**HENRY**, Tuesday, August 17, 2010 at 4:56pm1. (X^2 + X - 6) / (X - 2).

Factor the trinomial:

(X + 3)(X - 2) / (X - 2) =

Cancel the (X - 2) factors:

X + 3.

2. 24b^4c^3 / 6b^2c = 4b^2c^2

3. (3p^2 + pq - 2q^2) / (p + 2)

Factor the trinomial using A*C Method:

A * C = 3 * -2 = -6,

3p^2 +3pq-2pq -2q^2

Group the 4 terms into factorable

pairs:

3p^2+3pq -2pq-2q^2,

3p(p + q) -2q(p + q),

Factor out (p + q):

(p + q) (3p - 2q) / (p + q),

CANCEL THE (P + q) factors:

3p - 2q.

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