math
posted by kamleen on .
i need help with operation with polynomial
1) (x^2 + x  6) / (x  2)=
2) 24b^4C^3 / 6b^2c=
3) (3p^2 + pq  2q^2)/ (p + q)=

1. (X^2 + X  6) / (X  2).
Factor the trinomial:
(X + 3)(X  2) / (X  2) =
Cancel the (X  2) factors:
X + 3.
2. 24b^4c^3 / 6b^2c = 4b^2c^2
3. (3p^2 + pq  2q^2) / (p + 2)
Factor the trinomial using A*C Method:
A * C = 3 * 2 = 6,
3p^2 +3pq2pq 2q^2
Group the 4 terms into factorable
pairs:
3p^2+3pq 2pq2q^2,
3p(p + q) 2q(p + q),
Factor out (p + q):
(p + q) (3p  2q) / (p + q),
CANCEL THE (P + q) factors:
3p  2q.