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The height of a rocket in meters t seconds after it is launched is approximated by the polynomial 0.5 at2 + vt + y where a is always -9.8, v is the initial velocity, and h is the initial height. A 300X was launched from a height of 10 meters. What was its height after 3 seconds?

  • math - ,

    Height(t) = -4.9t^2 + vt + 10

    so Height(3) = -4.9(9) + 3v+10
    = 3v - 34.1

    You will have to know v, the intital velocity, to find to find an actual numerical answer.

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