math
posted by jacob on .
The height of a rocket in meters t seconds after it is launched is approximated by the polynomial 0.5 at2 + vt + y where a is always 9.8, v is the initial velocity, and h is the initial height. A 300X was launched from a height of 10 meters. What was its height after 3 seconds?

Height(t) = 4.9t^2 + vt + 10
so Height(3) = 4.9(9) + 3v+10
= 3v  34.1
You will have to know v, the intital velocity, to find to find an actual numerical answer.