can someone help me with this radical numbers problem?

(2suare root 8)(2-square root 8) would it be 2 square root 4?

I get

4*sqrt8-2*8=4*2sqrt2-16

I have 2 interpretations of your problem:

1. (2 * sqrt 8) (2 * sqrt 8)
2. (2 * sqrt 8 ) (2 - sqrt 8)

I will solve both:

1. (2 * sqrt 8) (2 * sqrt 8) =
4 * 8 = 32.

2. (2 * sqrt 8) (2- sqrt 8) =
4 * sqrt 8 - 2 * 8 =
4 * sqrt (4*2) - 16 =
4 * 2 * sqrt 2 - 16 =
8 * sqrt 2 - 16 =
8(sqrt 2 - 2) = - 4.69.

Yes, I can help you with that radical numbers problem.

To simplify the expression (2√8)(2-√8), we can start by expanding it using the distributive property, which states that a(b + c) is equal to ab + ac.

Let's break down the expression step-by-step:

(2√8)(2-√8)
= 2 * √8 * 2 + 2 * √8 * (-√8) (using the distributive property)

Now, we can simplify each term separately.

The first term, 2 * √8 * 2, can be simplified as follows:
2 * √8 * 2 = 4√8
= 4 * √(4 * 2) (using the property √(a * b) = √a * √b)
= 4 * √4 * √2
= 4 * 2 * √2
= 8√2

The second term, 2 * √8 * (-√8), can be simplified as follows:
2 * √8 * (-√8) = -2 * 8
= -16

Now, when we add the two simplified terms together, we get:
8√2 - 16

Therefore, the simplified expression for (2√8)(2-√8) is 8√2 - 16.