Posted by Ian on .
Two cyclists leave towns 240km apart at the same time and travel toward each other. One cyclist travels 10km/h slower than the other. If they meet in 5 hours, what is the rate of each cyclisst?

Algebra 
bobpursley,
distance= rate*time
240=(v+v10)*5hrs where v is the faster velocity
solve for v. The other rider is v10. 
Algebra 
Anonymous,
8