Posted by **Lereesa** on Sunday, August 15, 2010 at 8:50am.

A 5m long ladder rests on a vertical wall. if the bottom of the ladder slides away from the wall at 1m/s, how fast is the angle between the lader and the ground changing when the bottom of the ladder is 3m from the wall?

- Calculus -
**drwls**, Sunday, August 15, 2010 at 9:05am
Let X be the distance of the bottom from the wall. Let A be the angle

X = 5 cos A

dX/dt = (dX/dA)*(dA/dt)

= -5 sin A* dA/dt

dA/dt = (1 m/s)(-1/5)(1/sinA)

In this case, sin A = 4/5 when X =3 m.

dA/dt will be in radians per second.

- Calculus -
**Anonymous**, Sunday, February 27, 2011 at 3:36pm
lalalallala

- Calculus -
**Anonymous**, Sunday, February 27, 2011 at 3:37pm
Sa sa sa sa =! sassaslalalaa.blah

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