total ionic equation for the reaction between hydrochloric acid and potassium hydroxide?KI(aq)A. K+ + I-
B. K2+ + I2-
C. K+(aq) + I-(aq)
D. K2+(aq) + I2-(aq)
Something is amiss here. You question talks about HCl and KOH and the answers give K and I.
To find the total ionic equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH), you need to know the chemical formulas of these two compounds.
The chemical formula for hydrochloric acid is HCl, and when it dissolves in water, it dissociates into H+ ions and Cl- ions. This can be written as:
HCl(aq) -> H+(aq) + Cl-(aq)
The chemical formula for potassium hydroxide is KOH, and when it dissolves in water, it dissociates into K+ ions and OH- ions. This can be written as:
KOH(aq) -> K+(aq) + OH-(aq)
Now, to write the total ionic equation, we need to combine the ions that are involved in the reaction. The key point to remember is that ions that appear on both sides of the equation and do not undergo a change are called "spectator ions" and can be omitted.
In this case, the K+ and OH- ions are spectator ions because they appear on both the reactant and product sides of the equation without undergoing any changes. Therefore, they can be omitted from the total ionic equation.
So, the total ionic equation for the reaction between hydrochloric acid and potassium hydroxide is:
H+(aq) + Cl-(aq) -> H2O(l)
Therefore, the correct answer is option C: K+(aq) + I-(aq).