Wednesday
November 26, 2014

Homework Help: Algebra 1

Posted by Tamir on Friday, August 13, 2010 at 9:41pm.

Hello, can someone check my answer the the question below?

When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. WHat is the original number?

My answer
Let t = the tens digit of the original number
Let u = the units digit of the original number

10t+u
10u+t

10u+t = 10t+u+9
u+t=11

10u+t = 10t+u+9
10u - u+t - 10t = 9
9u - 9t = 9

u+t = 11
u-t = 1
2u = 12
u = 6

u+t = 11
6+t = 11
t = 5

The original number is 56

Check:
10u+t = 10t+u+9
60+5 = 50+6+9
65 = 65
u+t = 11
6+5 = 11
11 = 11

Thanks in advance for the help. I am just about finished with Algebra, which means I am close to HS graduation.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

math ALGEBRA - When the digits of two-digits numbers are reversed, the new ...
Algebra - The units digit of a two-digit number is two more than four times the ...
Algebra 2 - The sum of the digits of a two-digit number is 9. If the digits are ...
Algebra - The units digit of a two digit number is 1 more than twice the tens ...
Algebra 1 - The sum of the digit of a two digit number is 13. If the digits are ...
algebra - The sum of the digits of a two-digit number is eleven. If the digits ...
Algebra - The units digit of a two-digit number is two more than four times the ...
algebra - A number consists of two digits. The sum of twice the tens digit an 5 ...
math - the sum of the digits in a three-digit number is 16.the ones digit is ...
math - The sum of the digits of a two-digit number is 14. If the numbers are ...

Search
Members