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December 20, 2014

December 20, 2014

Posted by **dave** on Friday, August 13, 2010 at 1:02pm.

The sum of the intergers from 1 through n is n(n+1)/2. the sum of the squares of the intergers from 1 through n is n(n+1)(2n+1)/6. The sum of the cubes of the integers from 1 through n is n squared(n+1)squared/4. Use the appropriate expressions to find the following values.

(A). The sum of the integers from 1 through 30.

(B) The sum of the squares of the integers from 1 through 30

(C) The sum of the cubes of integers from 1 through 30.

(D) The square of the sum of the integers from 1 though 30.

(E) The cube of the sum of integers from 1 through 30.

I's sure its much easier than what I am making it out to be. I tried working the problems but am lost in what it' asking.

- college math -
**Anonymous**, Friday, August 13, 2010 at 1:34pmThey have given you the formulas for each of the question for A, B, and C

I will do B

Sum of squares from 1 to n

= n(n+1)(2n+1)/6

so the sum of the squares from 1 to 30, n=30

just plug it in

sum of squares = 30(31)(61)/6 = 9455

do A and C the same way

Once you have the answer for A,

square that result for D

cube the result for A to get E

- college math -
**gigi**, Wednesday, January 26, 2011 at 2:59pmDuring a walk, Dave completed the first two miles at a pace of 3mph. He walked the next two miles at a pace of 4.5 mph. Would his walk take more, less or the samr time if he walked the entire distance of four miles at a steady pace of 3.5 mph?

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