Posted by **Teddy** on Friday, August 13, 2010 at 11:07am.

log(base 2)cotx - 2log(base 4)csc2x = log(base 2)cosx

the answer should be x = pi/3, 5pi/3

not sure how to work it out though, any help? I tried canceling the bases but that led to a dead end.

- algebra 2 logs and trig -
**bobpursley**, Friday, August 13, 2010 at 11:46am
Think about log2 and log4. If N is a number, log2(N)=1/2 log4(N)

I am uncertain if the second term is csc^2 x or csc 2x. But my hint above should lead you to the solution.

- algebra 2 logs and trig -
**Teddy**, Friday, August 13, 2010 at 11:57am
It's csc 2x, and I got it down to this before but I don't know if I can use your hint from there or if I should start from square one:

log(base 2)csc(x) = log(base 4)csc(4x^2)

Would that become the following?

log(base 2)csc(x) = 2log(base2)csc(4x^2)

- algebra 2 logs and trig -
**bobpursley**, Friday, August 13, 2010 at 9:29pm
no, of course not.

did you mean this?

2log2 cscx= log4 cscx

That is correct.

## Answer this Question

## Related Questions

- LOGARITHMS - HI THE QUESTION STATES THAT ONE SHOULD CALCULATE THE LOGS WITHOUT ...
- algebra 2 - log(base 2)csc(x) = log(base 4)csc(4x^2) I tried doing the log(base ...
- Algebra 2 - -Explain the difference between log base b (mn) and ( log base b of ...
- Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...
- Precalc - 1. 1/3log base 8 of (x+1)=2log base 8 of 3-(2/3)log base 8 of (x+1) 2...
- check! - here is the question: log5(x-4)= log7x solve for x. These are just base...
- Review of Logs - I can't seem to get the answer to this; the answer key says log...
- Trig - log base b 64 - log base b 16 = log base 4 16 solve for the variable.. i...
- Math - Bases - What is 12 base 5? Would you just divide 12 by five and get 2 (...
- math-logs - 1. logaB = 2 and logbC = 4, evaluate logcA *the lowercase letters ...

More Related Questions