In the theory of relativity, the mass of a particle with velocity v is

m=mo/(square root ((1- v^ 2)/ c^2))

where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?

i meant

what happens as v goes to c-

as v goes to c, v^2 becomes c^2 and c^2/c^2 = 1,, therefore m becomes mo/sqrt(1-1) or mo/0 which is undefined,,

according to this, no such thing can exist with speed equal to the speed of light,,

so there,, =)

As the velocity (v) of a particle approaches the speed of light (c) in the theory of relativity, the equation you provided becomes interesting. Let's examine what happens when v approaches c.

The equation you mentioned is the relativistic mass equation and it describes how the mass (m) of a moving particle depends on its velocity (v), rest mass (mo), and the speed of light (c). It can be stated as:

m = mo / √((1 - (v^2 / c^2)))

When v approaches c, the numerator of the fraction in the square root becomes 0. This is because (v^2 / c^2) approaches 1, and subtracting 1 from 1 results in 0. Therefore, the equation can be simplified as:

m = mo / √(0)

However, dividing by zero is undefined, so we cannot directly calculate the mass (m) when v equals c using this equation.

In the theory of relativity, as an object with mass accelerates towards the speed of light, its relativistic mass continues to increase. However, it is crucial to note that objects with mass cannot reach or exceed the speed of light according to the theory of relativity. As an object with mass approaches the speed of light, it requires an infinite amount of energy to reach that speed, which is not attainable.

Therefore, the equation you provided becomes undefined as the velocity approaches the speed of light.