Friday

March 6, 2015

March 6, 2015

Posted by **Jin** on Friday, August 13, 2010 at 3:31am.

m=mo/(square root ((1- v^ 2)/ c^2))

where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?

- math -
**Jin**, Friday, August 13, 2010 at 3:38ami meant

what happens as v goes to c-

- math -
**jai**, Friday, August 13, 2010 at 4:40amas v goes to c, v^2 becomes c^2 and c^2/c^2 = 1,, therefore m becomes mo/sqrt(1-1) or mo/0 which is undefined,,

according to this, no such thing can exist with speed equal to the speed of light,,

so there,, =)

**Answer this Question**

**Related Questions**

Calculus - I don't understand this question. Q. In the theory of relativity, the...

calculus - limits - In the theory of relativity, the mass of a particle with ...

Math - n the theory of relativity, the mass of a particle with speed v is m=f(v...

modern physics - relativity - A photon of energy E collides with a stationary ...

special relativity - A photon of energy E collides with a stationary particle ...

Physics - A particle of mass =6.50 kg moves with a velocity v1=x1i+y1j+z1k. A ...

Physics - A particle with m = 3.3E-27 kg is moving with a velocity of 6.0E7m/s. ...

physics £££ - according to einstein's mass energy relation M= m'/root[1-(v^2/c^2...

physics - Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, ...

physics emergerncyy! - A particle of mass m1 = 2.5 kg moving along the x axis ...