Monday

December 22, 2014

December 22, 2014

Posted by **Miranda** on Thursday, August 12, 2010 at 10:13pm.

3cos2x - 5cosx = 1

- trig -
**drwls**, Thursday, August 12, 2010 at 10:32pmUse cos2x = 2 cos^2x -1 and convert the equation to a second order polynomial in which cosx is the variable. There should be two possible values of cosx.

**Answer this Question**

**Related Questions**

Pre Cal - Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. My ...

Advanced Math - Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. ...

Pre Cal. - So I posted these...but no one answered them. Are they right? Solve ...

Maths - trig - Solve 3cos2x - 7cosx = 0, when 0<=x<=360 And also, find the...

Trig - Compute inverse functions to four significant digits. cos^2x=3-5cosx ...

Mathematics - Hi there, Can someone help me with the question: "Prove that the ...

Trig - solve to four decimal places 1.3224sinx + 0.4732=0 :for all real x values...

Trig - solve to four decimals places 5.0118 sinx - 3.1105=0 :for all real x ...

Trig - use a graphing utility to solve each equation, rounded to 2 decimal ...

Maths integration - Please help! These 2 questions are very similar, and i tried...