Posted by jess on Thursday, August 12, 2010 at 5:28pm.
first, represent:
let x = amount of 20% acid used (in mL)
let 100-x = amount of 100% acid used (since the total volume of the 2 acids mixed must be 100)
therefore,
0.2x + 1(100-x) = .4(100)
*note: 0.2 = 20%, 1 = 100%, .4=40%
0.2x + 100-x = 40
-0.8x=-60
x = 75 mL of 20% acid, and
100-x = 25 mL of 100% acid
so there,, i hope i was able to help.. =)
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