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December 19, 2014

December 19, 2014

Posted by **jess** on Thursday, August 12, 2010 at 5:28pm.

- algebra -
**jai**, Friday, August 13, 2010 at 5:19amfirst, represent:

let x = amount of 20% acid used (in mL)

let 100-x = amount of 100% acid used (since the total volume of the 2 acids mixed must be 100)

therefore,

0.2x + 1(100-x) = .4(100)

*note: 0.2 = 20%, 1 = 100%, .4=40%

0.2x + 100-x = 40

-0.8x=-60

x = 75 mL of 20% acid, and

100-x = 25 mL of 100% acid

so there,, i hope i was able to help.. =)

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