Posted by **Ka'Sandra ** on Wednesday, August 11, 2010 at 4:03pm.

Consider the equation 7x + 3y = 42.

Part 1: On your own paper, graph this equation using the slope-intercept method. In the space provided, explain, in words, each step of the procedure you used. Make sure to use complete sentences and correct grammar. (3 points)

Part 2: On your own paper, graph this equation using the intercepts method. In the space provided, explain, in words, each step of the procedure you used. Make sure to use complete sentences and correct grammar. (3 points)

- algebra -
**bobpursley**, Wednesday, August 11, 2010 at 4:29pm
I am not certain of your question about this. I will be happy to critique your thinking.

- algebra -
**Ka'Sandra **, Wednesday, August 11, 2010 at 4:42pm
I just need to show the work from getting the equation 7x + 3y = 42 into slope- intercept form. Then I need the step by step work for graphing it in intercepts form.

- algebra -
**Reiny**, Wednesday, August 11, 2010 at 4:59pm
Your equation is perfect for finding intercepts.

let x=0 , (put your little finger over the 7x term), then y = 14

let y = 0, ( put your little finger over the 3y term), then x = 6

so you have 2 nice points, (0,14) and (6,0)

to change to slope-yintercept form

3y = -7x + 42

y = (-7/3)x + 14

- algebra -
**Ka'Sandra **, Wednesday, August 11, 2010 at 5:11pm
Thank you!

- algebra -
**Henry**, Wednesday, August 11, 2010 at 5:56pm
1. 7X + 3Y = 42.

Convert the std form Eq to the slope-interceptform:

7X + 3Y = 42,

3Y = -7X + 42,

Y = -7/3X + 14, (Y = mx + b).

Our 1st point will be at the Y-int

where X is always 0.

P1(0 , 14).

Since our slope is neg. DECREASE

b by 7:

y = 14 - 7 = 7.

X = 3 = The denominator of the slope.

P2(3 , 7).

GRAPH: P1(0 , 14) , P2(3 , 7)

2. 7X + 3Y = 42

At the y-int., X = 0.

Calculate Y:

7(0) + 3Y = 42

3Y = 42

Y = 14.

P1(0 , 14).

At the X-INT, Y = 0.

Calculate X:

7X + 3(0) = 42,

7X = 42,

X = 6.

P2(6 , 0).

GRAPH: P1(0 , 14) , P2(6 , 0).

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