Posted by Ka'Sandra on Wednesday, August 11, 2010 at 4:03pm.
I am not certain of your question about this. I will be happy to critique your thinking.
I just need to show the work from getting the equation 7x + 3y = 42 into slope- intercept form. Then I need the step by step work for graphing it in intercepts form.
Your equation is perfect for finding intercepts.
let x=0 , (put your little finger over the 7x term), then y = 14
let y = 0, ( put your little finger over the 3y term), then x = 6
so you have 2 nice points, (0,14) and (6,0)
to change to slope-yintercept form
3y = -7x + 42
y = (-7/3)x + 14
Thank you!
1. 7X + 3Y = 42.
Convert the std form Eq to the slope-interceptform:
7X + 3Y = 42,
3Y = -7X + 42,
Y = -7/3X + 14, (Y = mx + b).
Our 1st point will be at the Y-int
where X is always 0.
P1(0 , 14).
Since our slope is neg. DECREASE
b by 7:
y = 14 - 7 = 7.
X = 3 = The denominator of the slope.
P2(3 , 7).
GRAPH: P1(0 , 14) , P2(3 , 7)
2. 7X + 3Y = 42
At the y-int., X = 0.
Calculate Y:
7(0) + 3Y = 42
3Y = 42
Y = 14.
P1(0 , 14).
At the X-INT, Y = 0.
Calculate X:
7X + 3(0) = 42,
7X = 42,
X = 6.
P2(6 , 0).
GRAPH: P1(0 , 14) , P2(6 , 0).
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