Posted by **Winsel** on Tuesday, August 10, 2010 at 10:20am.

An observer at A looks due north and sees a meteor with an angle of elevation of 70deg. At the same instant, another observer 30miles east of A, sees the same meteor and apprroximates its position as N 50deg W but fails to note its angle of elevation. Find the height of the meteor and its distance form A.

- trigonometry -
**Henry**, Tuesday, August 10, 2010 at 12:26pm
The line of sight of the 2nd observer

is represented by the hypotenuse of a rt triangle, and the height of the

meteor is represented by the ver. side

of the rt triangle.The acute angle bet.

ween the ver. side and hyp. = 50 deg.

The angle of elevation is equal to the

other acute angle or 40 deg.

Tan(40) = h/30,

h =30*Tan(40) = 25.2 =height of

meteor

Tan(70) = 25.2 / d,

d = 25.2/Tan(70) = 9.2 = distance of

meteor.

- trigonometry -
**Henry**, Tuesday, August 10, 2010 at 12:36pm
CORRECTION!!

Sin(70) = 25.2/d,

d = 25.2/Sin(70) =26.8.

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