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August 29, 2014

August 29, 2014

Posted by **Kee** on Monday, August 9, 2010 at 7:49am.

1. State the null and alternative hypothesis.

2. Identify the level of significance: Given at 0.05

- statistics -
**MathGuru**, Monday, August 9, 2010 at 7:43pmYou can probably use a chi-square for this kind of problem.

Hypotheses:

Ho: There was equal distribution of viewers across the channels.

Ha: There was unequal distribution of viewers across the channels.

If there was equal distribution across the channels, you would expect 50 viewers watching each channel (150/3 = 50).

You can use the chi-square formula to calculate the test statistic if you need to do so.

Once you have the chi-square value calculated, compare this test statistic with a value from the chi-square table using df = 2 (df = number of groups minus 1) and .05 level of significance.

If the test statistic calculated exceeds the value you find from the table, the null will be rejected (there is a difference). If the test statistic does not exceed the critical value from the table, the null will not be rejected (there is no difference).

I hope this will help.

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