Saturday

October 25, 2014

October 25, 2014

Posted by **Kee** on Monday, August 9, 2010 at 7:49am.

1. State the null and alternative hypothesis.

2. Identify the level of significance: Given at 0.05

- statistics -
**MathGuru**, Monday, August 9, 2010 at 7:43pmYou can probably use a chi-square for this kind of problem.

Hypotheses:

Ho: There was equal distribution of viewers across the channels.

Ha: There was unequal distribution of viewers across the channels.

If there was equal distribution across the channels, you would expect 50 viewers watching each channel (150/3 = 50).

You can use the chi-square formula to calculate the test statistic if you need to do so.

Once you have the chi-square value calculated, compare this test statistic with a value from the chi-square table using df = 2 (df = number of groups minus 1) and .05 level of significance.

If the test statistic calculated exceeds the value you find from the table, the null will be rejected (there is a difference). If the test statistic does not exceed the critical value from the table, the null will not be rejected (there is no difference).

I hope this will help.

**Answer this Question**

**Related Questions**

Statistics - In Los Angeles there are three network television stations, each ...

Data Management Grade 12 - A survey of 1000 television viewers conducted by a ...

Math Data management - A survey of 1000 television viewers conducted by a local ...

Math - On January 1, 1984 there were 548 more commercial television stations ...

MATH - Amtrail trains provide efficient, nonstop transportation between Los ...

please read my introduction for media bias. - This is my introduction to my ...

Economics - Opera CD buyers are located in New York and Los Angeles. At the ...

sample t-test - A major television network is trying to determine whether to ...

statistics - Lubbock, Texas ran a survey and determined that 27% of all ...

math - Most populated U.S cities City Population(millions) New york - 8.10 Los ...