Posted by Kee on Monday, August 9, 2010 at 7:49am.
You can probably use a chi-square for this kind of problem.
Hypotheses:
Ho: There was equal distribution of viewers across the channels.
Ha: There was unequal distribution of viewers across the channels.
If there was equal distribution across the channels, you would expect 50 viewers watching each channel (150/3 = 50).
You can use the chi-square formula to calculate the test statistic if you need to do so.
Once you have the chi-square value calculated, compare this test statistic with a value from the chi-square table using df = 2 (df = number of groups minus 1) and .05 level of significance.
If the test statistic calculated exceeds the value you find from the table, the null will be rejected (there is a difference). If the test statistic does not exceed the critical value from the table, the null will not be rejected (there is no difference).
I hope this will help.
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