Posted by Alex on Sunday, August 8, 2010 at 11:49am.
The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

algebra  PsyDAG, Sunday, August 8, 2010 at 12:16pm
From your description, I am not sure that the fencing is around the whole perimeter of the field. If it is:
L = W + 18
2L + 2W = 216
2(W + 18) + 2W = 216
Solve for W, then put value in the first equation to solve for L. Check by inserting both values into the second equation.

algebra  Sarah, Saturday, September 27, 2014 at 5:58pm
A rectangular field is 3 yards longer than twice its width. If the perimeter is 156 yards, how wide is the field?
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