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March 26, 2017

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The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

  • algebra - ,

    From your description, I am not sure that the fencing is around the whole perimeter of the field. If it is:

    L = W + 18

    2L + 2W = 216

    2(W + 18) + 2W = 216

    Solve for W, then put value in the first equation to solve for L. Check by inserting both values into the second equation.

  • algebra - ,

    A rectangular field is 3 yards longer than twice its width. If the perimeter is 156 yards, how wide is the field?

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