Homework Help: algebra

Posted by Alex on Sunday, August 8, 2010 at 11:49am.

The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

algebra - PsyDAG, Sunday, August 8, 2010 at 12:16pm
From your description, I am not sure that the fencing is around the whole perimeter of the field. If it is:

L = W + 18

2L + 2W = 216

2(W + 18) + 2W = 216

Solve for W, then put value in the first equation to solve for L. Check by inserting both values into the second equation.

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