Posted by **Alex** on Sunday, August 8, 2010 at 11:49am.

The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

- algebra -
**PsyDAG**, Sunday, August 8, 2010 at 12:16pm
From your description, I am not sure that the fencing is around the whole perimeter of the field. If it is:

L = W + 18

2L + 2W = 216

2(W + 18) + 2W = 216

Solve for W, then put value in the first equation to solve for L. Check by inserting both values into the second equation.

- algebra -
**Sarah**, Saturday, September 27, 2014 at 5:58pm
A rectangular field is 3 yards longer than twice its width. If the perimeter is 156 yards, how wide is the field?

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