posted by thimmaiah .
3CS2 + 6 NaOH==> 2 Na2CS3 + Na2CO3 + 3 H2O
how many grams of Na2CS3 are produced in the reaction of 65 ml of liquid CS2(d=1.26 g/ml) and 1.56 mol NaOH?
This is a limiting reagent problem.
Convert 65 mL CS2 to moles. moles - grams/molar mass. Grams is obtained from the density data.
a. Using the coefficients in the balanced equation, convert moles CS2 to moles Na2CS3.
b. Same procedure, convert moles NaOH to moles Na2CS3.
c. It is likely that the answer for a and be will be different which means one of them is wrong. The correct answer, in limiting reagent problems, is ALWAYS the smaller one.
d. Convert moles from part c to grams. g = moles x molar mass.
Post your work if you get stuck.