Posted by thimmaiah on Sunday, August 8, 2010 at 7:05am.
Let's call acetic acid HAc. It saves time in typing.
HAc + NaOH --> NaAc + H2O
moles HAc initially = M x L = ??
moles NaOH initially = M x L = ??
React the two (one is an acid, the other a base). The solution ends up with some salt formed, none of the NaOH remaining, and some HAc left over. This means a buffered solution since you have a weak acid and its salt (the NaAc is sodium acetate). Use the Henderson-Hasselbalch equation to solve for the pH.
Post your work if you get stuck.
what is henderson-hasselbach equation?
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