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November 28, 2014

November 28, 2014

Posted by **Bonnie** on Sunday, August 8, 2010 at 2:38am.

Can anyone help me with this please?

- Math..LCM -
**Reiny**, Sunday, August 8, 2010 at 3:29pm35b^6a^4 = 5*7*bbbbbbaaaa

5b^8a^5 = 5*bbbbbbbbaaaaa

21b^2a^8 = 3*7*bbaaaaaaaa

now we need a number which contains all of those

I see 3*5*7*aaaaaaaabbbbbbbb

= 105a^8b^8

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