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August 1, 2014

August 1, 2014

Posted by **Joyce** on Saturday, August 7, 2010 at 10:29pm.

- Algebra -
**Quidditch**, Saturday, August 7, 2010 at 10:37pmt = 3t^3 + 22t^2 + 8t

subtract t from both sides

3t^3 + 22t^2 + 7t = 0

t is common to each term

t(3t^2 + 22t + 7) = 0

So, t = 0 is one solution.

Factor 3t^2 + 22t + 7 to get the other two solutions.

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