Posted by
**mathsen** on
.

Let ABC be a triangle such that angle ACB = 135 degrees. Prove that

AB^2 = AC^2 + BC^2 + ¡Ì2 x AC x BC.

Monday

March 27, 2017
Posted by
**mathsen** on
.

Let ABC be a triangle such that angle ACB = 135 degrees. Prove that

AB^2 = AC^2 + BC^2 + ¡Ì2 x AC x BC.

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