Saturday

August 30, 2014

August 30, 2014

Posted by **Ann** on Friday, August 6, 2010 at 10:18pm.

The cost, in millions of dollars, to remove x % of pollution in a lake modeled by the equation C=6,000/200-2x^2

What is the cost to remove 20% of the pollutant?

Please help! Thanks!

- Axia Math 117 -
**Reiny**, Friday, August 6, 2010 at 11:26pmFirst of all, I don't think you meant to type the equation as you did, or else why not reduce it to

C = 3000 - 2x^2

So I will assume you meant

C = 6000/(200-2x^2)

Secondly, the way you defined x % , we would have to replace x with 20, and then your result would be

C = 6000/(200 - 800) which will result in a negative cost, thus making no sense.

If we replace 20% with 0.2, we would get

C = 6000/(200 - .08) = 30.012

but the cost of removing 90% would then be

6000/(200 - 1.62) = 30.24

which is only slightly higher than removing 20%.

This does not make sense to me, so please check the typing of the equation, and the definition of x

**Related Questions**

Algebra 1 - Well we are doing factoring and I don't quite understand this ...

Axia HIS-125 - Need axia SYLLABUS HIS-125 US HISTORY FROM 1865 TO 1945

algebra - Find the value of y for a given value of x, if x varies directly with ...

math - A bike costs $117. This is $12 more than 3 times the amount Tom saved ...

Axia College - Need help with solving the double equation problem. 3x + 2y = 3 ...

algelbra 2 - I have a 3.50 but have 7 disks problem and can't think straight, my...

AP Physics - Find the scalar product of the vectors in Figure P7.8, where è = ...

math - can anyone help please, i need a simple formula for working out taxes.if ...

COM/155 - Compare and contrast your abilities as an academic writer now as ...

eng02 - Assignment: Incorporating Statistics, Graphs, and Illustrations ...