Posted by Winsel on .
A passenger on a ship sailing north at 5.0 mph noticed that at noon a radio tower on land was due east of the slip. At 1:30pm, the bearing of the tower from the ship was S 35deg E. How far was the ship from the tower at 1:30pm?
D = 5mi/h * 1.5h = 7.5mi = Dist. north.
Dist. = 7.5mi / Cos(35) = 9.2mi =
Dist. from tower.