What are the coefficent balance of this chemical equation H2SO4+NaNO2---->NHO2+Na2SO4?
1,2,2,1
To determine the coefficient balance of a chemical equation, you need to ensure that the number of atoms on both sides of the equation is equal. In this case, we have:
H2SO4 + NaNO2 --> NHO2 + Na2SO4
To balance the equation, let's start with the elements that appear in only one compound on each side.
1. Starting with hydrogen (H), there are 2 hydrogen atoms in H2SO4 and no hydrogen atoms in NHO2. We can balance the hydrogen by placing a coefficient of 2 in front of NHO2:
H2SO4 + NaNO2 --> 2NHO2 + Na2SO4
2. Moving on to sulfur (S), there is 1 sulfur atom in H2SO4 and 1 sulfur atom in Na2SO4. The sulfur is already balanced.
H2SO4 + NaNO2 --> 2NHO2 + Na2SO4
3. For oxygen (O), we have 4 oxygen atoms in H2SO4 and 2 oxygen atoms in NaNO2. The total number of oxygen atoms on the reactant side is 4+2 = 6. On the product side, we have 2 oxygen atoms in NHO2 and 4 oxygen atoms in Na2SO4, totaling 2+4 = 6. Therefore, oxygen is balanced.
H2SO4 + NaNO2 --> 2NHO2 + Na2SO4
4. Finally, let's balance sodium (Na). There is 1 sodium atom in NaNO2 and 2 sodium atoms in Na2SO4. To balance sodium, we need to place a coefficient of 2 in front of NaNO2:
H2SO4 + 2NaNO2 --> 2NHO2 + Na2SO4
Now all the elements are balanced, and the final balanced chemical equation is:
H2SO4 + 2NaNO2 --> 2NHO2 + Na2SO4