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April 1, 2015

April 1, 2015

Posted by **Sharee** on Thursday, August 5, 2010 at 2:06pm.

Problem 1

w2 - 2w + 2 = 0

A) 2

B) 1

C) 0

Problem 2

1 - 7a2 = -7a - 2

A) 2

B) 1

C) 0

- Math -
**Damon**, Thursday, August 5, 2010 at 3:07pmw2 - 2w + 2 = 0

a = 1

b = -2

c = 2

b^2-4ac = 4-4(1)(2) = 4-8 = -4

sqrt (-4) is imaginary

no real solutions (although 2 complex solutions)

1 - 7a2 = -7a - 2

7a^2 -7a -3 = 0

b^2-4ac = 49 -4(7)(-3) = 133

sqrt 133 is real number >0

so two real solutions

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