Posted by **Jason** on Thursday, August 5, 2010 at 10:33am.

For what real number k does 3x^2 k factor as

3(x 2)(x + 2)?

Can someone please help with this question? I can not understand how it says to solve this in the book

- Algebra -
**Henry**, Monday, August 9, 2010 at 7:42pm
Y = 3X^2 + K

Vertex Form:

Y = a(X -h)^2 + k

= 3(X -0)^2 + K

Y = 3(X-2)(X+2),

= 3(X^2 -4)

= 3X^2 - 12

h = -b / 2a = 0 / 6 = 0.

K = Yv = 3*0^2 -12 = -12. V(0 , -12).

Let's use a positive 2 in the 1st

parenthesis of our factored Eq.

Y = 3(X + 2 )(X + 2) = 3(X + 2)^2 =

3(X^2 + 4X + 4) = 3X^2 + 12X + 12.

h = Xv = -b / 2a = -12 / 6 = -2.

This value of h does not agree with

our given Eq in which h = 0.

Therefore, -2 is the correct choice.

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