Wednesday

August 20, 2014

August 20, 2014

Posted by **Jetta** on Wednesday, August 4, 2010 at 9:46am.

2) x^2-8x+7/x^2+6x-7 = (x-7)/(x+7)

3) x^2-5x+6/x+4 times 3x+12/x-2 =3(x-3)

4)2x-3/5x+1 divided by 6x^2-13x+6/15x^2-7x-2=1

5) x^3-9x/x^2+11x+24 times x^2+7x-8/x^2-4x+3= x(x-3)(x-1)/(x+3)(x+8)

6) 4x-8/x^2-x-6 divided by x^3 +x^2-6x/x^2-9=(x-3)/x(x-2)

7) x^2-16/x-3 divided x+4/x^2-9=(x-1)/(x+1)

- math -
**Jetta**, Wednesday, August 4, 2010 at 12:35pmare they correct?

- math -
**Henry**, Saturday, August 7, 2010 at 3:39pm4. (2X-3)/(4X-1) -Div by (6X^2-13X+6)/

(15X^2-7X-2).

Factor trinomial in numerator using A*C Method:

A*C = 6*6 = 36 = -4*-9,

6X^2 -4X-9X +6

Group the 4 terms in pairs and factor each pair:

2X(3X-2) -3(3X-2). Factor out (3x-2):

(3X-2) (2X-3).

Factor the trinomial in denominator

using A*C Method:

A*C = 15*-2 =-30 = 3*-10.

15X^2 +3X-10X -2.

Group the 4 terms in pairs and factor each pair:

3x(SX+1) -3(5X+1), Factor out (5x+1):

(5X+1) (3X-2).

Write original expression in factored form:

(2X-3)/(5X+1) Div by (3X-2)(2X-3)/

(5X+1)(3X-2).

Cancel the (3X-2) factors:

(2X-3)/5X+1) Div by (2X-3)/(5X+1).

Invert divisor and multiply:

(2X-3)/(5X+1) * (5X+1)/(2X-3).

Cancel the (5X+1) factors:

(2X-3)/(2X-3) = 1.

- math -
**Henry**, Sunday, August 8, 2010 at 4:15pm5. (X^3-9)/(X^2+11X+24) * (X^2+7X-8_/

(X^2-4X+3) =

Factor both numerators & denominators:

X(X^2-9)/(X+3)(X+8) * (X-1)(X+8)/

(X-1)(X-3) =

Cancel factors (X+8), and (X-1).

X(X^2-9)/(X+3) * 1/(X-3)

Factor (X^2-9):

X(X+3)(X-3)/(X+3) * 1/(X-3).

Cancel factors (x+3) & (X-3):

= X.

- math -
**Henry**, Monday, August 9, 2010 at 4:42pm6.(4X -8)/(X^2 -X -6) Div (X^3+X^26X)/

(X^2-9)

Factor completely:

4(X-2)/(X-3)(X+2) Div X(X^2+X-6)/(X+3)

(X-3).

4(X-2)/(X-3)(X+2) Div X(X+3)(X-2)/(X+3)(X-3).

Cancel factor (X+3) and invert divisor

4(X-2)/(X-3)(X+2) * (X-3)/X(X-2).

Cancel factors (X-2), (Z-3)

4/X(X+2).

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