find the domain of function
f(x)= (5x + 4)/(x^2 + 3x + 2)
is the answer..
x can't be -2 or -1?
how do you properly write the answer?
yes, x must not be equal to -2 and -1
(-00,-2)U(-2,-1)U(-1,+00)
*00==>infinity symbol (it should look like an 8 rotated 90 degrees clockwise..)
*U==>union
i hope i was able to help you.. =)
To find the domain of a function, we need to determine all the possible values that x can take. In this case, the function is a rational function, which means the denominator cannot equal zero.
So, to find the domain of the function f(x) = (5x + 4)/(x^2 + 3x + 2), we need to find the values of x that make the denominator equal to zero.
The denominator x^2 + 3x + 2 can be factored as (x + 1)(x + 2). Setting this equal to zero and solving for x, we get:
(x + 1)(x + 2) = 0
Now, we set each factor equal to zero:
x + 1 = 0 or x + 2 = 0
Solving these equations, we find that x = -1 or x = -2. These are the values of x that make the denominator equal to zero.
Therefore, the domain of the function f(x) = (5x + 4)/(x^2 + 3x + 2) is all real numbers except x = -1 and x = -2. In interval notation, the domain can be written as (-∞, -2) ∪ (-2, -1) ∪ (-1, ∞).