Posted by Todd on .
A 1.10 kg} block of wood sits at the edge of a table, 0.790 m above the floor. A 1.10×10−2 kg} bullet moving horizontally with a speed of 725 m/s embeds itself within the block.
What horizontal distance does the block cover before hitting the ground?
Use conservation of momentum to find the momentum of the block/bullet after impact, then the velocity. Now, knowing the initial horizonal velocity, you are on your way.
From the height above the floor, find the time it takes to fall.
.79=1/2 g t^2 find t.
Now horiztal distance willbe horizontal veloctiy*time.